JEE Main Result 2020: How to calculate percentile and All India Rank – education

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The JEE Main 2020 results are just around the corner and most students would be trying to know the way to calculate the Percentile and All India Rank.

JEE Main 2020 result would be decided through the process of normalisation. The exam used to be held on different days and sessions. It is fairly imaginable some candidates may get an easy paper while others might have to respond to tougher questions in JEE Main 2020 exam paper. To make certain that no aspirant benefits or is at a disadvantage because of this, the process of normalisation would be adopted to decide JEE Main results and ranks. NTA would rank students based on the percentile score obtained in the exam. This percentile score would be calculated as per a pre-determined formula.

What is Percentile Score?

The percentile score would be based on the relative performance of all of the aspirants appearing in the exam. The score would be obtained after transforming the scores into a scale ranging from 100 to 0 for each and every session of examinees.

As per the official NTA website, “The Percentile Score indicates the percentage of candidates that have scored EQUAL TO OR BELOW (same or lower uncooked scores) that specific Percentile in that examination. Due to this fact, the topper (highest score) of each and every session gets the same Percentile of 100 which is desirable. The marks obtained in between the highest and lowest scores are also converted to appropriate Percentiles.”

Difference between Percentage and Percentile

Percentile and the percentage of marks are two completely different entities. Thus, aspirants must not confuse both the above terms. Here’s the difference:

Percentage: Percentage is a number out of 100

Percentile : Percentile score of a candidate would mirror how many candidates have scored below that candidate in an exam. A Percentile score is the value below which a sure percent of observations fall.

Declaration of the last JEE Main 2020 result and All India Ranks

NTA conducted JEE Main 2020 in two attempts – January and September. Since the exam used to be held in more than one shifts every day across the two sessions, the calculation of score to a unmarried percentile score is done through a normalization process.

What is Normalization?

Normalisation is the process of identifying a candidate’s actual merit/rank by creating the same level playing field for each and every student. The very process is used in other exams across the country to unravel similar issues.

The formula to calculate JEE Main 2020 scores is:

NTA, to keep away from bunching effect and minimize tie-breaking, calculates the percentile scores up to 7 decimal places.

Steps Involved in normalisation and preparation of JEE Main 2020 merit/rank list:

Step-1: Distribution of examinees in two days and in two shifts per day

Candidates would be distributed into four sessions randomly in order that each and every session has an about equal number of candidates. These four sessions are as follows:

•Session-1: Day-1 Shift-1

•Session-2: Day-1 Shift-2

•Session-3: Day-2 Shift-1

•Session-4: Day-2 Shift-2

Step 2: Preparation of results for each and every Session

JEE Main 2020 results for each and every session would be prepared in the form of:

•Uncooked Scores

•Percentiles Scores one at a time for each and every of the three subjects (Mathematics, Physics, Chemistry) and the complete score.

•The following four percentiles would be calculated for each and every candidate in a session:

Step 3: Compilation of NTA score and preparation of overall merit/rank list

The percentile scores for the complete Uncooked Score of all of the four sessions as calculated in the above step would be merged and referred to as NTA scores. This would then be used for the compilation of result and preparation of overall JEE Main 2020 Merit List / Ranking.

Please note that the percentile of all four sessions would be calculated one at a time to decide the complete Uncooked Score and Uncooked Scores in three subjects: Mathematics, Physics, and Chemistry.

Compilation and display of JEE Result 2020 for multi-session

Compilation of JEE Main 2020 Result for the first attempt:

The first attempt of JEE Main 2020 used to be held in multi-session, thus, NTA scores would be calculated corresponding to the uncooked marks secured by a student in each and every session according to the process above. The NTA scores calculated for all of the sessions would be merged to declare JEE Main 2020 result. The result would comprise all of the four NTA scores for each and every of the three subjects: Mathematics, Physics, and Chemistry at the side of the complete of the first attempt.

Compilation of JEE Main 2020 result for the second one attempt:

The same above provided method would be followed to compile JEE Main results 2020 for the second one attempt.

Compilation of Result and Preparation of Merit List / Ranking

The four NTA scores of each and every candidate’s first and second attempts would be merged for the compilation of JEE Main result and preparation of overall Merit List/Ranking. Candidates who appeared in both the attempts, their best of the two NTA scores would be thought to be for the preparation of Merit List /Rankings. The method is explained in the following example:

JEE Main Result 2020: Tie-Breaking Resolution

In case two or more candidates protected equal percentile scores in JEE Main 2020 result, then the ranking would be decided in the following way:

Tiebreaker for Paper 1(BTech):

•NTA score in Mathematics: Candidate who secures more percentile score in Mathematics would be ranked higher

•NTA score in Physics: Candidate who secures more percentile score in Physics would be ranked higher

•NTA score in Chemistry: Candidate who secures more percentile score in Chemistry would be ranked higher

•Date of Birth: The older candidate would be ranked higher

Note: In case the tie still stands unresolved, the same rank is provided to the candidates

JEE Main 2020 Tiebreaker for Paper 2 (BArch):

•NTA score in Mathematics: Candidate who obtains higher marks in the mathematics would be provided a higher rank

•NTA score in Aptitude Test: Next, whether the tie still persists, then aspirant with a higher score in the aptitude test would be allotted a higher rank

•NTA score in Drawing Test: Whether the tie still persists, then aspirants with higher scores in the drawing test would be allotted a higher rank

•Lesser negative response: Candidates having lesser number of negative responses in the paper.

•Date of Birth: The older candidate would be ranked higher

JEE Main 2020 Tiebreaker for Paper 3 (B. Planning):

•NTA score in Mathematics: Aspirants who obtain higher marks in the mathematics would be provided a higher rank

•NTA score in Aptitude Test: Whether the tie persists, then aspirant with higher scores in the aptitude test would be provided a higher rank

•NTA score in Planning Based Questions: Whether the above criteria do not break the tie, then the candidate would higher marks in planning-based questions would be provided the higher rank

•Lesser negative response: Candidates having lesser number of negative responses in the paper.

•Date of Birth: The older candidate would be ranked higher

What After JEE Main 2020 Result?

•Cutoff for JEE Advanced

NTA would announce the cut-off score for JEE Advanced. In 2019, the cut-off score for general category students used to be 89.75 while that of OBC – NCL students used to be 74.

Counselling/Selection Procedure

After JEE Main and JEE Advanced results would be declared, JoSAA conducts joint seat allocation process for admissions to 100 institutes including 23 IITs, 31 NITs, 25 IIITs and 28 Other GFTIs. Admission to a majority of these JEE Main and JEE Advanced participating institutes would be done through a unmarried counselling platform.

(Writer of this article is an expert at FITJEE. Views expressed here are personal. )

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